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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    The magnetic flux through a circuit of resistance R changes by\[\Delta \phi \]in times\[\Delta t\]. Then, the total amount of electric charge that passes in any point in the circuit during this time\[\Delta t\] will be

    A)  \[Q=\frac{\Delta \phi }{R}\]                       

    B)  \[Q=\Delta \phi .R\]

    C)  \[Q=\frac{R\Delta t}{\Delta \phi }\]                       

    D)  \[Q=\Delta t.R\]

    Correct Answer: A

    Solution :

                    From Faradays law of EMI. emf induced in the circuit is \[e=\frac{\Delta \phi }{\Delta t}\] If\[R\]is the resistance in the circuit, then                 \[I=\frac{e}{R}=\frac{\Delta \phi }{\Delta t.R}\] So, the total amount of charge passing through the circuit is                 \[Q=I\times \Delta t=\frac{\Delta \phi }{\Delta t.R}.\Delta t\] \[\Rightarrow \]               \[Q=\frac{\Delta \phi }{R}\]


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