question_answer

In the given reaction, The products X and Y respectively are

A)  a-bromo nitrobenzene and o-bromoaniline

B)  p-bromo nitrobenzene and p-bromoaniline

C)  m-bromo nitrobenzene and m-bromoaniline

D)  o, p-dibromonitrobenzene and o, p-dibromoaniline

Correct Answer: C

Solution :

                  Nitro group is a deactivating and m-directing group hence it direct the incoming\[B{{r}^{-}}\]ion to the\[m-\]position, thus leading to the formation of\[m-\]bromonitrobenzene. By reduction with \[Sn/HCl,\]the nitro group reduces to\[-N{{H}_{2}}\] i.e. the final product is m-bromoaniline.