A) \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Cu\]
B) \[Cu\xrightarrow[{}]{{}}C{{u}^{2+}}+2{{e}^{-}}\]
C) \[2{{H}_{2}}O\xrightarrow[{}]{{}}4{{H}^{+}}+{{O}_{2}}+4{{e}^{-}}\]
D) \[{{H}_{2}}O+{{e}^{-}}\xrightarrow[{}]{{}}O{{H}^{-}}+\frac{1}{2}{{H}_{2}}\]
Correct Answer: C
Solution :
\[CuS{{O}_{4}}+aq\xrightarrow[{}]{{}}C{{u}^{2+}}(aq)+SO_{4}^{2-}(aq)\] \[{{H}_{2}}O{{H}^{+}}+O{{H}^{-}}\] At anode \[O{{H}^{-}}\xrightarrow[{}]{{}}OH+{{e}^{-}}\] \[4OH\xrightarrow[{}]{{}}2{{H}_{2}}O+{{O}_{2}}\] \[\therefore \]Net reaction is\[2{{H}_{2}}O\xrightarrow[{}]{{}}4H+{{O}_{2}}+4{{e}^{-}}\]
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