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NEET NEET SOLVED PAPER 2016 Phase-I

  • question_answer
    Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape?

    A)  1/8                                       

    B)  ¼

    C)   3/8                                      

    D)   ½

    Correct Answer: A

    Solution :

                     \[{{n}_{{{H}_{2}}}}={{n}_{{{O}_{2}}}}\]and \[{{t}_{{{H}_{2}}}}={{t}_{{{O}_{2}}}}\] According to Graham's law \[\frac{{{r}_{{{H}_{2}}}}}{{{r}_{{{O}_{2}}}}}=\sqrt{\frac{{{M}_{{{O}_{2}}}}}{{{M}_{{{H}_{2}}}}}}\Rightarrow \frac{{{v}_{1}}/{{t}_{1}}}{{{v}_{2}}/{{t}_{2}}}=\sqrt{\frac{32}{2}}\] \[\frac{1/2}{1/x}=\sqrt{16}=4\] \[\frac{x}{2}=4\] \[\therefore \] \[x=8\] \[\therefore \]  Fraction of \[{{O}_{2}}=1/8\]


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