A) \[{{101}^{o}}C\]
B) \[{{100}^{o}}C\]
C) \[{{102}^{o}}C\]
D) \[{{103}^{o}}C\]
Correct Answer: A
Solution :
\[\left( \frac{{{P}^{0}}-{{P}_{s}}}{{{P}^{0}}} \right)=\frac{n}{N}=\frac{{{w}_{solute}}}{{{M}_{solute}}}\times \frac{{{M}_{solvent}}}{{{W}_{solvent}}}\] at \[100{{\,}^{o}}C,\,\,{{P}^{o}}=760\,\,mm\] \[\frac{760-732}{760}=\frac{6.5\times 18}{{{M}_{solute}}\times 100}\] \[{{M}_{solute}}=31.75\,g\,\text{mo}{{\text{l}}^{-1}}\] \[\Delta {{T}_{b}}=m\times {{K}_{b}}=\frac{{{w}_{solute}}\times 1000}{{{M}_{solute}}\times {{w}_{solvent}}}\times {{K}_{b}}\] \[\Delta {{T}_{b}}=\frac{0.52\times 6.5\times 1000}{31.75\times 100}=1.06{{\,}^{o}}C\] \[\therefore \]boiling point of solution \[={{100}^{o}}C+{{1.06}^{o}}C\simeq 101{{\,}^{o}}C\]
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