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NEET NEET SOLVED PAPER 2017

  • question_answer
    The resistance of a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length, its new resistance will be                                                                                                                                                                          

    A) \[\frac{R}{{{n}^{2}}}\]                                   

    B)  \[nR\]

    C)   \[\frac{R}{n}\]                                

    D)  \[{{n}^{2}}R\]

    Correct Answer: D

    Solution :

                     \[\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{l_{2}^{2}}{l_{1}^{2}}\]                 \[=\frac{{{n}^{2}}l_{1}^{2}}{l_{1}^{2}}\]                 \[\frac{{{R}_{2}}}{{{R}_{1}}}={{n}^{2}}\]                 \[{{R}_{2}}={{n}^{2}}{{R}_{1}}\]


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