A) \[C{{H}_{3}}=C{{H}_{3}}>C{{H}_{2}}=C{{H}_{2}}>C{{H}_{3}}-C=CH>CH=CH\]
B) \[C{{H}_{2}}=C{{H}_{2}}>C{{H}_{3}}-CH=C{{H}_{2}}>C{{H}_{3}}-C\equiv CH>\]\[CH\equiv CH\]
C) \[CH\equiv CH>C{{H}_{3}}-C\equiv CH>C{{H}_{2}}=C{{H}_{2}}>C{{H}_{3}}-C{{H}_{3}}\]
D) \[CH\equiv CH>C{{H}_{2}}=C{{H}_{2}}>C{{H}_{3}}-C\equiv CH>C{{H}_{3}}-C{{H}_{3}}\]
Correct Answer: D
Solution :
Correct order is\[\underset{\begin{smallmatrix} (Two\,acidic \\ hydrogens) \end{smallmatrix}}{\mathop{H-C\equiv C-H>}}\,\underset{\begin{smallmatrix} (One\,acidic \\ hydrogen) \end{smallmatrix}}{\mathop{{{H}_{3}}C-C\equiv C-H>}}\,{{H}_{2}}C=C{{H}_{2}}\]\[>C{{H}_{3}}-C{{H}_{3}}\]
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