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  • question_answer
    Correct increasing order for the wavelengths of absorption in the visible region for the complexes of \[C{{o}^{3+}}\]is                                                                                                                                                                              

    A) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]

    B) \[{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]

    C) \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}},{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{(N{{H}_{3}}O)}_{6}}]}^{3+}}\]

    D)  \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}},{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{(e{{n}_{3}})}_{3}}]}^{3+}}\]

    Correct Answer: B

    Solution :

                                    The order of the ligand in the spectrpcemical series \[{{H}_{2}}O<N{{H}_{3}}<en\] Hence, the wavelength of the light observed will be in the order \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}<{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}<{{[Co{{(en)}_{3}}]}^{3+}}\] Thus, wavelength absorbed will be in the opposite order i.e.,  \[{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]


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