A) Nitrogen family, \[[Rn]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{6}}\]
B) Halogen family, \[[Rn]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{5}}\]
C) Carbon family, \[[Rn]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{2}}\]
D) Oxygen family,\[[Rn]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{4}}\]
Correct Answer: C
Solution :
Z = 114 belong to Group 14, carbon family Electronic configuration\[=[Rn]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{2}}\]
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