Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    A body of mass \[5\,\,kg\] moving with a velocity \[10\,\,m/s\] collides with another body of the mass \[20\,\,kg\] at rest and conies to rest. The velocity of second due to collision will be

    A) \[10\,\,m/s\]                    

    B) \[7.5\,\,m/s\]

    C) \[2.5\,\,m/s\]                   

    D) \[5\,\,m/s\]

    Correct Answer: C

    Solution :

    Mass of the first body\[{{m}_{1}}=5\,\,kg\] Velocity of first body before collision \[{{v}_{1}}=10\,\,m/s\] Mass of the second body\[{{m}_{2}}=20\,\,kg\] velocity of first body after collision \[v=0\] From the law of conservation of momentum \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}\] \[5\times 10+20\times 0=5\times 0+20\times {{v}_{2}}\]                 \[20{{v}_{2}}=50\]    or    \[{{v}_{2}}=2.5\,\,m/s\] (\[{{v}_{2}}\] is velocity of second body after collision)


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