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Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    If\[|\overset{\to }{\mathop{A}}\,\times \overset{\to }{\mathop{B}}\,|=|\overset{\to }{\mathop{A}}\,.\overset{\to }{\mathop{B}}\,|\]then the angle between\[\overset{\to }{\mathop{A}}\,\]and\[\overset{\to }{\mathop{B}}\,\]is

    A) \[{{90}^{o}}\]                                    

    B) \[{{60}^{o}}\]

    C) \[{{45}^{o}}\]                                    

    D) \[{{30}^{o}}\]

    Correct Answer: C

    Solution :

    The modulus of cross and dot product of vectors \[\overset{\to }{\mathop{A}}\,\] and \[\overset{\to }{\mathop{B}}\,\] is \[AB\sin \theta \] and\[AB\cos \theta \]. Hence, the given condition \[AB\sin \theta =AB\cos \theta \] \[\tan \theta =1=\theta ={{45}^{o}}\]


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