2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-1999

  • question_answer
    In an apparatus, the electric field was found to oscillate with an amplitude of\[18\,\,V/m\]. The magnitude of the oscillating magnetic field is

    A) \[6\times {{10}^{-8}}tesla\]                        

    B) \[3\times {{10}^{-8}}tesla\]

    C) \[12\times {{10}^{-8}}tesla\]      

    D) \[9\times {{10}^{-8}}tesla\]

    Correct Answer: A

    Solution :

    Amplitude of electric field\[{{E}_{0}}=18\,\,V/m\] The magnitude of the oscillating magnetic field \[{{E}_{0}}=\frac{{{E}_{0}}}{c}=\frac{18}{3\times {{10}^{8}}}=6\times {{10}^{-8}}tesla\]


You need to login to perform this action.
You will be redirected in 3 sec spinner