A) \[70%\]
B) \[35%\]
C) \[90%\]
D) \[100%\]
Correct Answer: A
Solution :
Using the relation for the efficiency of Carnot engine. We have \[\eta =\left( 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right)\times 100\] (given:\[{{T}_{2}}=273+27=300\,\,K\] \[{{T}_{1}}=727+273=1000\,\,K)\] \[\eta =\left( 1-\frac{300}{1000} \right)\times 100\] \[=70%\]
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