A) \[60\,\,{{\pi }^{2}}\,\,m/{{s}^{2}}\]
B) \[80\,\,{{\pi }^{2}}\,\,m/{{s}^{2}}\]
C) \[120\,\,{{\pi }^{2}}\,\,m/{{s}^{2}}\]
D) \[144\,\,{{\pi }^{2}}\,\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
Here: Frequency\[f=60\,\,Hz\] Amplitude\[a=0.01\,\,m\] Using the relation the maximum acceleration is given by \[={{\omega }^{2a}}a={{(2\pi f)}^{2}}a\] \[={{(2\times \pi )}^{2}}\times {{(60)}^{2}}\times 0.01\] \[=144{{\pi }^{2}}\,\,m/{{s}^{2}}\]
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