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Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    A stone is thrown with an initial speed of \[4.9\,\,m/s\] from a bridge in vertically upward direction. It falls down in water after\[2\sec \]. The height of bridge is:

    A) \[24.7\,\,m\]                     

    B) \[19.8\,\,m\]

    C) \[9.8\,\,m\]                       

    D) \[4.9\,\,m\]

    Correct Answer: C

    Solution :

    Here: initial velocity\[xv=-4.9\,\,m/s(-ve\] is due to vertically upward motion) Total time\[t=2\sec \] The height of the bridge is given by                 \[s=ut+\frac{1}{2}g{{t}^{2}}\]                    \[=-4.9\times 2+\frac{1}{2}\times 9.8\times {{(2)}^{2}}\]                    \[=-9.8+19.6=9.8\,\,m\]


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