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Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
    A siren emitting sound of frequency 500 Hz is going away from a stationary listener with a speed of\[50\,\,m/s\], the frequency of sound to be heard directly from the siren is:

    A) \[286.5\,\,Hz\]                 

    B) \[481\,\,Hz\]

    C) \[434.2\,\,Hz\]                 

    D) \[580\,\,Hz\]

    Correct Answer: C

    Solution :

    Here: frequency of siren\[=500\,\,Hz\] The speed of siren\[{{v}_{s}}=50\,\,m/s\] Using Dopplers principle\[n=\frac{v}{v+{{v}_{s}}}n\] or            \[n=\left( \frac{330}{330+50} \right)\times 500\] or            \[n=\frac{330\times 500}{380}=434.2\,\,Hz\]


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