Punjab Medical Punjab - MET Solved Paper-2003

  • question_answer
     A circular coil of mean radius of\[7\,\,cm\] and having 4000 turns is rotated at the rate of 1800 revolutions per minute in the earths magnetic field (\[B=0.5\]gauss), the emf induced in coil will be:

    A) \[1.158\,\,V\]                   

    B) \[0.58\,\,V\]

    C) \[0.29\,\,V\]                      

    D) \[5.8\,\,V\]

    Correct Answer: B

    Solution :

    Here:\[n=4000,\,\,B=0.5\times {{10}^{-4}}\,\,wb/{{m}^{2}}\] Rate of rotation of coil\[=1800\,\,rev/\min \]                 \[=\frac{1800}{60}=30\,\,rev/\sec \]                 \[gw=2\pi f=2\pi \times 30=60\pi \,\,rad/s\] \[r=7\,\,cm=0.07\,\,m\] Now area of coil                 \[A=\pi {{r}^{2}}=\pi \times {{(0.07)}^{2}}\]                     \[=49\pi \times {{10}^{-4}}{{m}^{2}}\] Now the maximum energy induced is \[e=BA\,\,n\omega \] \[=0.5\times {{10}^{-4}}\times 49\pi \times {{10}^{-4}}\times 4000\times 60\pi \] \[=0.58\,\,V\]


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