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Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    If the current through \[3\Omega \] resistor is\[0.8\,\,A\], then potential drop through \[4\Omega \] resistor is:

    A) \[1.5\,\,V\]                        

    B) \[2.6\,\,V\]

    C) \[4.8\,\,V\]                        

    D) \[9.8\,\,V\]

    Correct Answer: C

    Solution :

    Current across the \[3\Omega \] resistor \[=0.8A\] The current through the parallel resistance of \[6\Omega \] is                 \[=\frac{0.8\times 3}{6}=0.4\,\,A\] Hence, the total current across \[Q\] is                 \[=0.8+0.4=1.2\] Now, potential across \[4\Omega \] resistor is                 \[=4\times 1.2=4.8\]


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