2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-2004

  • question_answer
    At \[{{25}^{o}}C\] the specific conductivity of a normal solution of \[KCl\] is\[0.002765\,\,mho\]. The resistance of cell is\[400\,\,ohms\]. The cell constant is:

    A) \[0.815\]                             

    B) \[1.016\]

    C) \[1.106\]                             

    D) \[2.016\]

    Correct Answer: C

    Solution :

    We know that cell constant\[\text{=}\frac{\text{specific}\,\,\text{conductivitty}}{\text{obsereved}\,\,\text{conductance}}\] Here, specific conductance\[=0.002765\]observed conductance\[=\frac{1}{R}\]\[=\frac{1}{400}\] \[\therefore \]cell constant\[=0.002765\times 400\]\[=1.106\]


You need to login to perform this action.
You will be redirected in 3 sec spinner