A) \[{{C}_{6}}{{H}_{5}}-NH-C{{H}_{3}}\]
B) \[{{C}_{6}}{{H}_{5}}-COOH\]
C) \[{{C}_{6}}{{H}_{5}}-C{{H}_{2}}-N{{H}_{2}}\]
D) \[{{C}_{6}}{{H}_{5}}-C{{H}_{2}}-COOH\]
Correct Answer: B
Solution :
\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\xrightarrow{NaN{{O}_{2}}/HCl}{{C}_{6}}{{H}_{5}}{{N}_{2}}Cl\]\[\xrightarrow{C{{u}_{2}}{{(CN)}_{2}}}\underset{(Y)}{\mathop{{{C}_{6}}{{H}_{5}}CN}}\,\xrightarrow{{{H}_{2}}O/{{H}^{+}}}\] \[\underset{benzoic\,\,acid\,\,(Z)}{\mathop{{{C}_{6}}{{H}_{5}}-COOH}}\,\] Thus, product \[Z\] is identified as\[{{C}_{6}}{{H}_{5}}-COOH.\]
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