A) \[12\times {{10}^{-6}}J\]
B) \[9\times {{10}^{-4}}J\]
C) \[4.5\times {{10}^{-6}}J\]
D) \[2.25\times {{10}^{-6}}J\]
Correct Answer: B
Solution :
Given:\[C=6\mu F,\,\,{{V}_{1}}=10\,\,volt\], \[{{V}_{2}}=2\,\,volt\] Increase in energy \[E=\frac{1}{2}CV_{2}^{2}-\frac{1}{2}CV_{1}^{2}\] \[=\frac{1}{2}C(V_{2}^{2}-V_{1}^{2})\] \[=\frac{1}{2}\times 6\times {{10}^{-6}}({{20}^{2}}-{{10}^{2}})\] \[=3\times {{10}^{-6}}({{20}^{2}}-{{10}^{2}})\] \[=3\times {{10}^{-6}}\times 300=9\times {{10}^{-4}}\text{J}\]
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