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Punjab Medical Punjab - MET Solved Paper-2005

  • question_answer
    The normality of mixture obtained by mixing \[100ml\] of \[0.2\,\,M\,\,{{H}_{2}}S{{O}_{4}}+100\,\,ml\] of\[0.2\,\,M\,\,NaOH\]is:

    A) \[0.2\]                                  

    B) \[0.01\]

    C) \[0.1\]                                  

    D) \[0.3\]

    Correct Answer: C

    Solution :

    Miliequivalents of \[{{H}_{2}}S{{O}_{4}}=100\times 0.2\times 2=40\] Miliequivalents of \[NaOH=100\times 0.2\times 2=40\] Miliequivalents of \[{{H}_{2}}S{{O}_{4}}\] left after neutralization\[=40-20=20\] Total volume of the solution \[=100+100=200ml\] Normality of\[{{H}_{2}}S{{O}_{4}}(left)=\frac{20}{200}=0.1N\]


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