A) \[C{{H}_{3}}CHO\]
B) \[C{{H}_{3}}COOH\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]
D) \[C{{H}_{3}}-C{{H}_{2}}COOH\]
Correct Answer: A
Solution :
Acetaldehyde give both Tollens reagent and Fehlings solution test Acetaldehyde reduce Tollens reagent to give silver mirror. \[C{{H}_{3}}-CH=O+2{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}}+3O{{H}^{-}}\]\[\xrightarrow{{}}C{{H}_{3}}COOH+\underset{\begin{smallmatrix} \,\,silver \\ mirror \end{smallmatrix}}{\mathop{2Ag}}\,+4N{{H}_{3}}+{{H}_{2}}O\]and acetaldehyde reduce fehling solution to red cuprous oxide. \[C{{H}_{3}}CHO+\underset{(Fehling\,\,solution)}{\mathop{2C{{u}^{+2}}+5O{{H}^{-}}}}\,\xrightarrow{{}}C{{H}_{3}}COOH\]\[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,red\,\,p.pt \\ (cuprous\,\,oxide) \end{smallmatrix}}{\mathop{+C{{u}_{2}}O\downarrow }}\,+3{{H}_{2}}O\]
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