A) \[Fe{{(OH)}_{3}}\]
B) \[Zn{{(OH)}_{2}}\]
C) \[Al{{(OH)}_{3}}\]
D) \[Sn{{(OH)}_{2}}\]
Correct Answer: A
Solution :
\[Fe{{(OH)}_{3}}\]ferric hydroxide is not soluble in\[NaOH\] \[Zn{{(OH)}_{2}}+2NaOH\xrightarrow{{}}N{{a}_{2}}Zn{{O}_{3}}+2{{H}_{2}}O\] \[Al{{(OH)}_{3}}+NaOH\xrightarrow{{}}NaAl{{O}_{2}}+2{{H}_{2}}O\] \[Sn{{(OH)}_{2}}+2NaOH\xrightarrow{{}}N{{a}_{2}}Sn{{O}_{2}}+2{{H}_{2}}O\]
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