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Punjab Medical Punjab - MET Solved Paper-2006

  • question_answer
    Molecular orbital electronic configuration for\[X\]anion is: \[KK*{{(\sigma 2s)}^{2}}{{(\sigma *2s)}^{2}}{{(\pi 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{(\sigma 2{{p}_{z}})}^{2}}\]\[{{(\pi *2{{p}_{x}})}^{1}}\]. The anion \[X\] is:

    A) \[N_{2}^{-}\]                                    

    B) \[O_{2}^{-}\]

    C) \[N_{2}^{2-}\]                                  

    D) \[O_{2}^{2-}\]

    Correct Answer: A

    Solution :

    Given, electronic configuration of anion\[X\]is: \[\sigma 1{{s}^{2}},\,\,\sigma *1{{s}^{2}},\,\,\sigma 2{{s}^{2}},\,\,\sigma *2{{s}^{2}},\,\,\sigma 2p_{x}^{2},\,\,\pi 2p_{y}^{2},\,\,\sigma 2p_{z}^{2}\] \[\pi *2p_{x}^{1}\] \[\therefore \]total number of electrons of anion\[X=15\] Hence, the anion \[X\] is\[N_{2}^{-}\].


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