A) \[\alpha -\]particle
B) \[\beta -\]particle
C) \[\gamma -\]particle
D) proton
Correct Answer: D
Solution :
\[_{Z}^{A}X+_{2}^{4}He\xrightarrow{{}}_{Z+3}^{A+3}Y+D\] The product D is\[_{1}^{1}H,i.e.,\]proton. \[\because \]sum of atomic numbers of reactants = sum of atomic numbers of products and sum of mass numbers of reactants = sum of mass numbers of products
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