A) Balmer series
B) Lyman series
C) Paschan series
D) Pound series
Correct Answer: C
Solution :
For hydrogen spectrum from Bohrs theory \[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] \[\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)=\frac{1}{\lambda R}\] \[=\frac{1}{18752\times {{10}^{-10}}\times 1.097\times {{10}^{7}}}\] \[=\frac{486}{10000}=\frac{7}{144}\] \[=\frac{{{4}^{2}}-{{3}^{2}}}{{{3}^{2}}\times {{4}^{2}}}\] \[=\left( \frac{1}{{{3}^{2}}}-\frac{1}{{{4}^{2}}} \right)\] \[\Rightarrow \] \[{{n}_{1}}=3,\,\,{{n}_{2}}=4\] It is true for Paschan series.
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