Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    A black body radiates \[20W\] temperature\[{{227}^{o}}C\]. If temperature of the black body is changed to \[{{727}^{o}}C\] then its radiating power will be

    A) \[120W\]                            

    B) \[240W\]

    C) \[320W\]                            

    D) \[360W\]

    Correct Answer: C

    Solution :

    For a black body\[\frac{Q}{t}=P=A\sigma {{T}^{4}}\] \[\Rightarrow \]\[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\Rightarrow \,\,\,\,\frac{{{P}_{2}}}{20}={{\left( \frac{273+727}{273+227} \right)}^{4}}\] \[\Rightarrow \]\[\frac{{{P}_{2}}}{20}={{(2)}^{4}}\]    \[\Rightarrow \]    \[{{P}_{2}}=320W\]


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