2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-2008

  • question_answer
    A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of\[3s\]. If the field strength is increased to\[4\] times of the earlier field strength, the time period will be (in seconds)

    A)  12                                         

    B)  6

    C)  1.5                                        

    D)  0.75

    Correct Answer: C

    Solution :

    \[T=2\pi \sqrt{\frac{I}{MB}}\] or            \[T\propto \frac{1}{\sqrt{B}}\] or            \[\frac{{{T}_{2}}}{3}=\sqrt{\frac{1}{4}}\]    or     \[{{T}_{2}}=1.5\,\,s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner