A) \[\frac{hv}{4}\]
B) \[\frac{hv}{3}\]
C) \[\frac{hv}{2}\]
D) \[\frac{2hv}{3}\]
Correct Answer: D
Solution :
\[\frac{\frac{1}{2}m{{v}^{2}}}{\frac{1}{2}m{{(2v)}^{2}}}=\frac{hv-\phi }{h(2v)-\phi }\] or \[\frac{1}{4}=\frac{hv-\phi }{2hv-\phi }\] or \[\phi =\frac{2hv}{3}\]
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