2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-2008

  • question_answer
    The magnitude of maximum acceleration is \[\pi \] times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in second is

    A)  4                                            

    B)  2

    C)  1                                            

    D)  0.5

    Correct Answer: B

    Solution :

    Maximum acceleration = Maximum velocity\[\times \,\,\pi \]ie,                                           \[{{\omega }^{2}}A=\pi \omega A\] where\[A\]is amplitude and \[\omega \] is angular velocity. \[\Rightarrow \]               \[\omega =\pi \] \[\Rightarrow \]               \[\frac{2\pi }{T}=\pi \]     \[\Rightarrow \]     \[T=2s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner