A) \[24,630c{{m}^{-1}}\]
B) \[24,360c{{m}^{-1}}\]
C) \[24,730c{{m}^{-1}}\]
D) \[24,372c{{m}^{-1}}\]
Correct Answer: D
Solution :
\[\bar{v}=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For Balmer series, \[{{n}_{1}}=2\] and for 4th line in Balmer series\[{{n}_{2}}=6\] \[\because \] \[R=109677c{{m}^{-1}}\] \[v=109677\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{6}^{2}}} \right)\] \[=109677\left( \frac{1}{4}-\frac{1}{36} \right)\] \[v=24,372c{{m}^{-1}}\]
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