A) \[N{{H}_{3}}\]
B) \[{{H}_{2}}O\]
C) \[BC{{l}_{3}}\]
D) None of these
Correct Answer: D
Solution :
\[BC{{l}_{3}}\]has bond angle equal to\[{{120}^{o}}\](trigonal planar).\[N{{H}_{3}}\]and\[{{H}_{2}}O\]have\[s{{p}^{3}}\] hybridisadon but due to the presence of lone pair of electrons, they have bond angle less than\[109{}^\circ 28\]\[(N{{H}_{3}}-107{}^\circ ,\,\,{{H}_{2}}O-104.5{}^\circ )\],\[As{{H}_{3}}\]\[(s{{p}^{3}}\]hybridised) has smaller bond angle than\[N{{H}_{3}}\]due to less electronegativity of As than\[N.\]
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