A) \[NaCl\]
B) \[CuCl\]
C) \[CuC{{l}_{2}}\]
D) \[CsCl\]
Correct Answer: C
Solution :
According to Fajans rule, as the size of cation decrease, its polarising power increases. Hence, \[C{{u}^{2+}}\] polarise \[C{{l}^{-}}\] ions more than\[C{{u}^{+}},\] Therefore, \[CuC{{l}^{2}}\] has more covalent character and hence, its boiling point is less.
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