A) \[16\times {{10}^{-7}}Nm\]
B) \[64\times {{10}^{-7}}Nm\]
C) \[48\times {{10}^{-7}}Nm\]
D) \[32\times {{10}^{-7}}Nm\]
Correct Answer: D
Solution :
Deflecting couple is given by \[\tau =MH\sin \theta \] ... (i) where \[M=\]magnetic moment = pole strength x effective length \[=2\times 10\times {{10}^{-2}}\] \[=2\times {{10}^{-1}}A{{m}^{2}}\] \[H=\]horizontal component of earths magnetic field \[=0.32\times {{10}^{-4}}T\] and \[\theta ={{30}^{o}}\] From Eq. (i), we get \[\tau =2\times {{10}^{-1}}\times 0.32\times {{10}^{-4}}\times \sin {{30}^{o}}\] \[=0.64\times {{10}^{-5}}\times \frac{1}{2}\] \[=0.32\times {{10}^{-5}}Nm\] \[=32\times {{10}^{-7}}Nm\]
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