Punjab Medical Punjab - MET Solved Paper-2009

  • question_answer
    Consider following reactions \[I:C(s)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}CO(g);\,\,\Delta {{H}_{1}}=a\] (b)\[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g);\,\,\Delta {{H}_{2}}=b\] (c)\[C(s)+C{{O}_{2}}(g)\xrightarrow{{}}2CO(g);\Delta {{H}_{3}}=c\] Select correct statement

    A)  Heat of formation of\[C{{O}_{2}}\]is\[(a+b)\]

    B)  Heat of combustion of\[C\]is\[(a+b)\]

    C) \[\Delta {{H}_{3}}=\Delta {{H}_{1}}-\Delta {{H}_{2}}\]

    D)  All the above are correct statements

    Correct Answer: D

    Solution :

    I:\[C(s)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}CO(g);\]\[\Delta {{H}_{1}}=a\] II:\[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g);\]\[\Delta {{H}_{2}}=b\] III:\[C(s)+C{{O}_{2}}(g)\xrightarrow{{}}2CO(g);\]\[\Delta {{H}_{3}}=c\] On adding Eq. I and II, we get \[C(s)+{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g);\,\,\Delta H=\Delta {{H}_{1}}+\Delta {{H}_{2}}\]                                                                           \[=a+b\] \[\therefore \]Heat of formation of\[C{{O}_{2}}=a+b\] and heat of combustion of\[C=a+b\] On subtracting Eq II from I, we get \[C(s)+C{{O}_{2}}(g)\xrightarrow{{}}2CO(g);\,\,{{H}_{3}}=\Delta {{H}_{1}}-\Delta {{H}_{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner