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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    Typical silt (hard mud) particle of radius\[20\mu m\]is on the top of lake water, its density is \[2000kg/{{m}^{3}}\] and the viscosity of lake water is\[1.0mPa\], density is\[1000\text{ }kg/{{m}^{3}}\]. If the lake is still (has no internal fluid motion) the terminal speed with which the particle hits the bottom of the lake is in\[mm/s\]

    A) \[0.67\]                               

    B) \[0.77\]

    C) \[0.87\]                                

    D) \[0.97\]

    Correct Answer: C

    Solution :

    Terminal velocity                 \[v=\frac{2}{9}\frac{{{r}^{2}}(\rho -\sigma )g}{\eta }\]                   \[=\frac{2}{9}\times \frac{{{(20\times {{10}^{-6}})}^{2}}(2000-1000)\times 9.8}{1.0\times {{10}^{-3}}}\]                   \[=8.7\times {{10}^{-4}}m/s=0.87mm/s\]


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