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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    Compound\[A\]on reduction gives\[B\], which on further reaction with\[CHC{{l}_{3}}\]and alcoholic\[KOH\] gives compound\[C\], which on further hydrolysis gives aniline. The compound\[A\]is

    A)  nitrobenzene                  

    B)  methylamine

    C)  nitromethane                  

    D)  nitro sobenzene

    Correct Answer: A

    Solution :

    \[\underset{A}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,\xrightarrow[Sn/Cl]{\operatorname{Re}d}\underset{B}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,\xrightarrow[CHC{{l}_{3}}]{KOH}\underset{C}{\mathop{{{C}_{6}}{{H}_{5}}NC}}\,\]                                \[\xrightarrow[Boil]{{{H}_{2}}O}\underset{aniline}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+HCOOH\] Hence, the compound A is nitrobenzene.


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