Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    The standard emf of a cell, involving one electron change is found to be \[0.591V\] at\[{{25}^{o}}C.\] The equilibrium constant of the reaction is\[(F=96500\,\,C\,\,mo{{l}^{-1}})\]

    A) \[1.0\times {{10}^{1}}\]                

    B) \[1.0\times {{10}^{5}}\]

    C) \[1.0\times {{10}^{10}}\]                             

    D) \[1.0\times {{10}^{30}}\]

    Correct Answer: C

    Solution :

    \[E{{{}^\circ }_{cell}}=\frac{2.303RT}{nF}\log {{K}_{eq}}(at\,\,298\,\,K)\] \[E{{{}^\circ }_{cell}}=\frac{0.0591}{1}\log {{K}_{eq}}\] \[0.591=\frac{0.0591}{1}\log \,\,{{K}_{eq}}\]                 \[\log \,\,{{K}_{eq}}=10\] \[\therefore \]  \[{{K}_{eq}}=1\times {{10}^{10}}\]


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