A) \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\]
B) \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\]
C) \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\]
D) \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]\]
Correct Answer: A
Solution :
(a)\[\underset{(1\,\,mol)}{\mathop{[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}}}\,+\underset{(excess)}{\mathop{3AgN{{O}_{3}}}}\,\xrightarrow{{}}\] \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3AgCl\downarrow +3NO_{3}^{-}\] (b)\[[Co{{(N{{H}_{3}})}_{5}}Cl]Cl+2AgN{{O}_{3}}\xrightarrow{{}}\] \[{{[Co{{(N{{H}_{3}})}_{5}}Cl]}^{2+}}+2NO_{3}^{-}+2AgCl\downarrow \] (c)\[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]cl+2AgN{{O}_{3}}\xrightarrow{{}}\] \[{{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}NO_{3}^{-}+AgCl\downarrow \] (d)\[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]+AgN{{O}_{3}}\xrightarrow{{}}\]No reaction Hence, \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\] on treatment with excess of\[AgN{{O}_{3}}\], gives maximum amount of\[AgCl\].
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