Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    Two masses\[M\]and\[m\]are attached to a vertical axis by weightless thread of combined length\[l.\] They are set in rotational motion in a horizontal plane about this axis with constant angular velocity\[\omega \]. If the tensions in the thread are same during motion, the distance of M from the axis is,

    A) \[\frac{Ml}{M+m}\]                       

    B) \[\frac{ml}{M+m}\]

    C) \[\frac{M+m}{M}l\]                       

    D) \[\frac{M+m}{m}l\]

    Correct Answer: B

    Solution :

    \[mr{{\omega }^{2}}=MR{{\omega }^{2}}\] Put         \[r=l-R\] \[\therefore \]  \[m(l-R)=MR\] \[\Rightarrow \]               \[R=\frac{ml}{M+m}\]


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