Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    A body of mass \[5kg\] is moving with a momentum of\[10\,kg\,m/s\]. A force of\[0.2\,\,N\]acts on it in the direction of motion of the body for 10 s. The increase in its kinetic energy is

    A) \[2.8\,\,J\]                         

    B) \[3.2\,\,J\]

    C) \[3.8\,\,J\]                         

    D) \[4.4\,\,J\]

    Correct Answer: D

    Solution :

    \[Change\,\,in\,\,momentum=force\times time\] \[\Rightarrow \]               \[{{p}_{2}}-{{p}_{1}}=0.2\times 10=2kg\,\,m/s\] \[\Rightarrow \]               \[{{p}_{2}}={{p}_{1}}+2=10+2=12\,\,kg\,\,m/s\] Increase in\[KE=\frac{1}{2m}(p_{2}^{2}-p_{1}^{2})\]                 \[=\frac{1}{2\times 5}[{{(12)}^{2}}-{{(10)}^{2}}]\]                 \[=\frac{1}{10}\times (144-100)\]                 \[=4.4\,\,J\]


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