Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    A\[50\,\,V\]potential difference is suddenly applied to a coil with\[L=5\times {{10}^{-2}}\]and\[R=180\Omega \]. The rate of increase of current after\[0.001s\]is

    A) \[27.3\,\,A/s\]                  

    B) \[27.8\,\,A/s\]

    C) \[2.73\,\,A/s\]                  

    D) \[2.78\,\,A/s\]

    Correct Answer: A

    Solution :

    Equation of current in \[L-R\] circuit                 \[I={{I}_{0}}(1-{{e}^{Rt/L}})\] Rate of increase of current                 \[\frac{dI}{dt}={{I}_{0}}\frac{R}{L}{{e}^{-Rt/L}}\]                 \[=\frac{V}{L}{{e}^{-Rt/L}}\]                       \[(\because \,\,V={{I}_{0}}R)\]                 \[=\frac{50}{5\times {{10}^{-2}}}{{e}^{-(180\times 0.01)/5\times {{10}^{-2}}}}\]                 \[=27.3\,\,A/s\]


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