Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    The kinetic energy of an electron is\[5eV\]. Calculate   the   de-Broglie   wavelength associated  with  it\[(h=6.6\times {{10}^{-34}}J\,\,s,\]\[{{m}_{e}}=9.1\times {{10}^{-31}}kg)\]

    A) \[5.47\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B) \[10.9\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[2.7\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) None of the above

    Correct Answer: A

    Solution :

    \[\lambda =\frac{h}{\sqrt{2m\,\,KE}}\] \[=\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 5\times 1.6\times {{10}^{-19}}}}\] \[=5.469\times {{10}^{-10}}m=5.47\overset{\text{o}}{\mathop{\text{A}}}\,\]


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