A) \[400\,\,yr\]
B) \[300\,\,yr\]
C) \[200\,\,yr\]
D) \[193\,\,yr\]
Correct Answer: A
Solution :
Decay constant,\[k=\frac{0.693}{{{t}_{1/2}}}\] \[=\frac{0.693}{100}y{{r}^{-1}}\] Also, decay constant \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[\Rightarrow \] \[k=\frac{2.303}{t}\log \frac{100}{100-93.75}\] \[=\frac{0.693}{100}=\frac{2.303}{t}\log 16\] \[\therefore \] \[t=\frac{2.303\times 100\times 4\times 0.3010}{0.693}\]
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