RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    What will be the moment of inertia of a ring about tangential axis in its plane?

    A)  \[M{{R}^{2}}\]        

    B)  \[2M{{R}^{2}}\]

    C)  \[\frac{3}{2}M{{R}^{2}}\]

    D)  None of these

    Correct Answer: C

    Solution :

     Moment of inertia about diameter of ring \[=\frac{1}{2}M{{R}^{2}}\] From theorem of parallel axis \[I={{I}_{CM}}+M{{R}^{2}}\] \[=\frac{1}{2}M{{R}^{2}}+M{{R}^{2}}\] \[=\frac{3}{2}M{{R}^{2}}\]


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