A) 5 : 3 : 1
B) 1 : 4 : 9
C) 1 : 3 : 5
D) 9 : 4 : 1
Correct Answer: C
Solution :
Travelling distance in first second, \[{{s}_{1}}=0\times 1+\frac{1}{2}g\times {{(1)}^{2}}=\frac{1}{2}g\] After one second achieve velocity, \[v=0+g\times 1=g\] Travelling distance after 2 second, \[{{s}_{2}}=g\times 1+\frac{1}{2}g\times {{(1)}^{2}}=\frac{3}{2}g\] Velocity, \[v=g+g{{(1)}^{2}}=2g\] Travelling distance in third second, \[{{s}_{3}}=2g\times 1+\frac{1}{2}g\times {{(1)}^{2}}=\frac{3}{2}g\] Thus\[{{s}_{1}}:{{s}_{2}}:s{{ & }_{3}}=1:3:5\]
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