A) 0.5%
B) 1%
C) 2%
D) 0.2%
Correct Answer: A
Solution :
\[T\propto \sqrt{l}\] \[\Rightarrow \] \[\frac{{{T}_{1}}+\frac{x}{100}{{T}_{1}}}{{{T}_{1}}}=\sqrt{\frac{l+\frac{l}{100}}{l}}\] Or \[1+\frac{x}{100}=\sqrt{0.01}\] Or \[x=0.5%\]
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