RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    Choose the correct relation. (where p = pressure, E = kinetic energy of gas)

    A)  \[p=\frac{3}{2}E\]

    B)  \[p=\frac{2}{3}E\]

    C)  \[p=\frac{1}{2}E\]

    D)  \[p=\,2E\]

    Correct Answer: B

    Solution :

     Pressure of ideal gas \[p=\frac{1}{3}\frac{mN}{V}v_{rms}^{2}\] \[=\frac{1}{2}Mv_{rms}^{2}\] \[=\frac{2}{3}.\left( \frac{1}{2}Mv_{rms}^{2} \right)\] \[=\frac{2}{3}E\]


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