A) 170 \[\Omega \]
B) 70 \[\Omega \]
C) 130 \[\Omega \]
D) 120 \[\Omega \]
Correct Answer: C
Solution :
Impedance \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] Now \[IR=100\] \[\Rightarrow \] \[R=\frac{100}{2}=50\,\Omega \] and \[{{X}_{L}}=\frac{240}{2}=120\,\Omega \] \[\therefore \] \[Z=\sqrt{{{(50)}^{2}}+{{(120)}^{2}}}\] \[=\sqrt{16900}=130\,\Omega \]
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